Air Race from Metropolis to Aniba Gothic and Back

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In summary, an aircraft in an air race travels from Metropolis to Gothic city and back at a constant speed of v with respect to the air. Gothic city is located D distance to the East of Metropolis. The time required for the flight with a constant wind speed of w in the East direction is 2Dv/(v^2-w^2). The time required for the flight with a wind blowing towards the South is 2d/sqrt(v^2-w^2).
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leprofece
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3.82 in an air race, an aircraft flies from a point directly above Metropolis to a point directly city aniba Gothic, turn and return at starting point. The speed of the aircraft with respect to the air is constant in all the flight and equal to v. city is Gothic a distance D to the East of Metropolis. (Cuanto tiempo se requiere si sepla un viento con rapidez constante w b) to the East? (c) towards the South?

Answer b) \frac{2Dv}{v^2-w^2} I have no idea of this answer It should be 2d/v-w

c) \frac{2d}{\sqrt{v^2-w^2}}}
 
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in an air race, an aircraft flies from a point directly above Metropolis to a point directly on the top of Gothic city, turn and return at starting point. The speed of the aircraft with respect to the air is constant in all the flight and equal to v. city is Gothic a distance D to the East of Metropolis. (How much time is required if a wind blows at constant speed w b) to the East? (c) towards the South?

Answer b) \frac{2Dv}{v^2-w^2} I have no idea of this answer It should be 2d/v-w

c) \frac{2d}{\sqrt{v^2-w^2}}}
 

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