- #1
Vig16
- 7
- 0
I'm trying to cool 8 ounces of 70 deg C water down to 38 deg C. I want to do this all in 2 minutes, but with as low a cost as possible. I was thinking of using a fan or air pressure of some short to do this. The only question I had is how do I determine the pressure or amount of air that I'll need to obtain the temperature drop?
My initial test was to dispense 3 ounces at 70dC and then have room temperature water dispensed into the 70dC water. In my two attempts at this, I got the temperature in the cup down to 44dC and 47dC, but am still off by a bit. I was thinking that if I introduced air of some sort into the flow of room temperature water, that I'd be able to have the final water temp drop the 5-10dC that I'm looking for.
Does anyone have any insight as to how I'd go about calculating the amount of cooling that I'd need to get to the desired temperature? Even just the equation to start with would be greatly appreciated!
Thanks so much!
My initial test was to dispense 3 ounces at 70dC and then have room temperature water dispensed into the 70dC water. In my two attempts at this, I got the temperature in the cup down to 44dC and 47dC, but am still off by a bit. I was thinking that if I introduced air of some sort into the flow of room temperature water, that I'd be able to have the final water temp drop the 5-10dC that I'm looking for.
Does anyone have any insight as to how I'd go about calculating the amount of cooling that I'd need to get to the desired temperature? Even just the equation to start with would be greatly appreciated!
Thanks so much!