- #1
mertcan
- 345
- 6
hi, initially I am aware that AICc value is $$ -2(*log-likelihood)+2K+2K*(K+1)/(n-K-1)$$ where n is sample size and K is number of model parameters. But I really do not know how last term of right hand side is added, also AIC value is $$ -2*(log-likelihood)+2K$$ , so AICc has some correction in addition to AIC. In short my question is what is the derivation of correction in AICc $$(2K*(K+1)/(n-K-1) )$$ ??