Algebra help about polynomials

In summary, the function f(x) is a fourth degree polynomial with zeros of plus or minus 2 and plus or minus 3i. Its general form is f(x)=ax^4+bx^3+cx^2+dx+e, and it can be expressed as f(x)=k(x^2-4)(x^2+9) where k is a constant. By setting f(0)=-108, we can find the value of k and fully determine the equation for f(x).
  • #1
kelly
2
0
I really need help.
f(x) is a fourth degree polynomial function
f(x) has zeros of plus or minus 2 and plus or minus 3i
f(0)=-108
Find an equation for f(x) in general form
 
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  • #2
Hello and welcome to MHB, kelly! :D

The general quartic having the zeroes \(\displaystyle x\in\{a,b,c,d\}\) is given by:

\(\displaystyle f(x)=k(x-a)(x-b)(x-c)(x-d)\) where \(\displaystyle k\ne0\)

Can you state the family of quartics with the given roots?
 
  • #3
kelly said:
I really need help.
f(x) is a fourth degree polynomial function
f(x) has zeros of plus or minus 2 and plus or minus 3i
f(0)=-108
Find an equation for f(x) in general form

$f(x)$ is a fourth degree polynomial function, so it is of the form $f(x)=ax^4+bx^3+cx^2+dx+e$.

$f(0)=-108 \Rightarrow e=-108$What can we deduce from the fact that $f(x)$ has zeros of plus or minus $2$ and plus or minus $3i$ ?
 
  • #4
I am unsure. That was all of the information received. I was absent and i have no idea how to even begin this problem
 
  • #5
kelly said:
I am unsure. That was all of the information received. I was absent and i have no idea how to even begin this problem

$f(x)$ has zeros of plus or minus $2$ and plus or minus $3i$ means that:

$$f(2)=0 \\ f(-2)=0 \\ f(3i)=0 \\ f(-3i)=0$$

What can we get from the above relations? You just have to substitute the values.
 
  • #6
kelly said:
I really need help.
f(x) is a fourth degree polynomial function
f(x) has zeros of plus or minus 2 and plus or minus 3i
f(0)=-108
Find an equation for f(x) in general form

MarkFL said:
Hello and welcome to MHB, kelly! :D

The general quartic having the zeroes \(\displaystyle x\in\{a,b,c,d\}\) is given by:

\(\displaystyle f(x)=k(x-a)(x-b)(x-c)(x-d)\) where \(\displaystyle k\ne0\)

Can you state the family of quartics with the given roots?
Using MarkFL's method we know that, with a = 2, b = -2, c = 3i, d = -3i, we have
\(\displaystyle f(x) = k(x - 2)(x + 2)(x - 3i)(x + 3i) = k(x^2 - 4)(x^2 + 9)\)

Then \(\displaystyle f(0) = -108 = k(0^2 - 4)(0^2 + 9) = -36k\) and now you can solve for k.

-Dan
 

FAQ: Algebra help about polynomials

What is a polynomial?

A polynomial is an expression consisting of variables, coefficients, and exponents, combined using addition, subtraction, and multiplication operations. It can have multiple terms, and each term can have a different degree.

What are the different types of polynomials?

The three main types of polynomials are monomials, binomials, and trinomials. A monomial has one term, a binomial has two terms, and a trinomial has three terms. Polynomials can also be classified by their degree, such as linear, quadratic, or cubic.

How do I add and subtract polynomials?

To add or subtract polynomials, combine like terms. Like terms have the same variables raised to the same powers. Add the coefficients of the like terms together and keep the variables and exponents the same.

How do I multiply polynomials?

To multiply polynomials, use the distributive property. Multiply each term of the first polynomial by each term of the second polynomial, then combine like terms to simplify the resulting expression.

How do I factor polynomials?

To factor polynomials, look for the greatest common factor (GCF) of all the terms. Use the distributive property to rewrite the polynomial as the GCF multiplied by the remaining terms. Then, factor each of the remaining terms as much as possible.

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