- #1
Pepala
- 4
- 0
I am going through my notes and I don't understand the steps that are being taken to get to the solution, any help in figuring this out would be greatly appreciated!
It starts off with two equations
[tex]x=\frac{k+θπ}{1+θ^2/Ω}[/tex]
and
[tex]π= \frac{θ}{Ω}(\frac{k+θπ}{1+θ^2/Ω})[/tex]
then multiply x by Ω/Ω and we get
[tex]x=\frac{Ω(k+θπ)}{Ω+θ^2}[/tex]
let z represent [tex]\frac{Ω}{Ω+θ^2}[/tex]
then
[tex]x=z (k+θπ^2)[/tex]
then,
[tex]π= (θ/Ω)z(k+πθ)[/tex]
now here is where i get lost
K+ θπ > C
[tex]θπ=\frac{θ^2}{Ω}z[/tex]
how do we get to the next step? if we divide by z then we get (θπ)/z but π= (θ/Ω)(K+π) so θπ= (θ/Ω)(K+π)(1/z)... then what?
[tex]\frac{θ^2}{Ω}=\frac{1-z}{z}[/tex]
[tex]θπ=\frac{1-z}{z}[/tex]
z(K+θπ)=(1-z)(K+θπ)
θπ- (1-z)θπ=(1-z)K
[tex]zθπ= (1-z)k => θπ= \frac{1-z}{z} (K) [/tex]
= K/z
I am hoping that someone can explain in detail ( because I can't follow this) the steeps in between each step here.
Thank you for your time
It starts off with two equations
[tex]x=\frac{k+θπ}{1+θ^2/Ω}[/tex]
and
[tex]π= \frac{θ}{Ω}(\frac{k+θπ}{1+θ^2/Ω})[/tex]
then multiply x by Ω/Ω and we get
[tex]x=\frac{Ω(k+θπ)}{Ω+θ^2}[/tex]
let z represent [tex]\frac{Ω}{Ω+θ^2}[/tex]
then
[tex]x=z (k+θπ^2)[/tex]
then,
[tex]π= (θ/Ω)z(k+πθ)[/tex]
now here is where i get lost
K+ θπ > C
[tex]θπ=\frac{θ^2}{Ω}z[/tex]
how do we get to the next step? if we divide by z then we get (θπ)/z but π= (θ/Ω)(K+π) so θπ= (θ/Ω)(K+π)(1/z)... then what?
[tex]\frac{θ^2}{Ω}=\frac{1-z}{z}[/tex]
[tex]θπ=\frac{1-z}{z}[/tex]
z(K+θπ)=(1-z)(K+θπ)
θπ- (1-z)θπ=(1-z)K
[tex]zθπ= (1-z)k => θπ= \frac{1-z}{z} (K) [/tex]
= K/z
I am hoping that someone can explain in detail ( because I can't follow this) the steeps in between each step here.
Thank you for your time
Last edited: