- #1
ali987
- 9
- 0
Hi everyone
Consider a 2x2 partitioned matrix as follow:
A = [ B1 B2 ; B3 B4 ]
I'm sure that all eigenvalues of A are on the unit circle (i.e., abs
(all eig) = 1 ). but, I don't know how to prove it. Is there any
theorem?
Consider a 2x2 partitioned matrix as follow:
A = [ B1 B2 ; B3 B4 ]
I'm sure that all eigenvalues of A are on the unit circle (i.e., abs
(all eig) = 1 ). but, I don't know how to prove it. Is there any
theorem?