Am I doing this problem correctly?

  • Thread starter bcjochim07
  • Start date
In summary, an ice cube weighing 50 g can slide without friction up and down a 30 degree slope. When pressed against a spring with a spring constant of 25 N/m, the ice cube compresses the spring by 10 cm. Upon release, the ice cube will travel a total distance of 37.9 cm up the slope before reversing direction. If the ice cube is replaced with a 50 g plastic cube with a coefficient of kinetic friction of 0.20, the plastic cube will travel a total distance of 37.9 cm up the slope. This is found by calculating the force of kinetic friction, using the change in thermal energy equation, and applying the conservation of energy equation.
  • #1
bcjochim07
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Homework Statement



a) A 50 g ice cube can slide without friction up and down a 30 degree slope. The ice cube is pressed against a spring at the bottom of the slope, compressing the spring 10 cm. The spring constant is 25 N/m. When the ice cube is released, what total distance will it travel up the slope before reversing direction?

b) The ice cube is replaced by a 50 g plastic cube whose coefficient of kinetic friction is 0.20. How far will the plastic cube travel up the slope?


Homework Equations


Us=.5kx^2
U=mgy
change in thermal energy= (force of kinetic friction)*(displacement)


The Attempt at a Solution


I got part a, and I want to make sure I am doing part b correctly.

Here's what I did.

Fk= mgcostheta * coefficient of friction
Fk= (.05kg)(9.80)(cos30)(.20)=.085 N

change in thermal energy= Fk* distance covered up slope (d)
change in thermal energy = .085 * d

I called y the final height so y=dsin30

Kf + Uf + change in thermal energy = Ki + Ui

(.05kg)(9.80)(dsin30) + (.085d) = (.5)(25 N/m)(.1m)^2
d= .379 m = 37.9 cm
 
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  • #2
Looks good.
 
  • #3



Your solution for part b is correct. You correctly used the equation for kinetic friction and the conservation of energy principle to solve for the distance traveled by the plastic cube up the slope. Good job!
 

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