- #1
SYoung
- 11
- 0
Homework Statement
The amplification of an integrator is:
A = Vout/Vin = -Zf/Zin = +j * 1/(ωRC)
The amplification of an differentiator is:
A = Vout/Vin = -Zf/Zin = -jωRC
Although, that's what my book says. Not that I doubt it..
But really, what do Zf, Zin, j, and ω stand for?
I can't find much about it.
The book only says the following:
ω = 1/(RC), but why? what does this mean?
and that Vout 90° lags (-j) at Vin, regardless the frequency.
Thus: A is (straight?) proportional with the increasing frequency, so increases with 6dB each octave/scale and with 20dB each decade/level.
But really, I have no idea what this actually means.
In the classes we didn't attend this to the matter and we don't have to know this for the upcoming exam. But I'm just curious ;)
Thanks in advance,
Young