An almost elementary differentiation problem....

In summary, "An almost elementary differentiation problem" is a mathematical problem that involves finding the derivative of a function using basic principles of differentiation, but may require some additional steps or techniques to solve. It is called "almost elementary" because it can be solved using basic principles, but may also require more advanced techniques. This type of problem can be challenging due to the need for a combination of rules and techniques, as well as a deeper understanding of differentiation concepts. The best approach to solving it is to identify the function, simplify it, and then apply the appropriate differentiation rules. Some tips for solving these problems include practicing, understanding the basic rules, and being familiar with additional techniques. It is also important to carefully read and understand the problem and double
  • #1
DreamWeaver
303
0
Let \(\displaystyle \zeta(x)\) be the Zeta function (where, for convenience, \(\displaystyle x\) is assumed to be \(\displaystyle > 1\)).

\(\displaystyle \zeta(x) = \sum_{k=1}^{\infty}\frac{1}{k^x}\)Similarly, define the Eta function (alternating Zeta function) by the following series - where again, in this case, we assume \(\displaystyle x > 1\):\(\displaystyle \eta(x) = \sum_{k=1}^{\infty}\frac{(-1)^{k+1}}{k^x}\)
Problem:Express the second derivative of the Eta function - at \(\displaystyle x=4\) - in terms of the Zeta function (differentiated or otherwise), at \(\displaystyle x=4\).
 
Mathematics news on Phys.org
  • #2
Isn't it just a matter of applying the product rule on $ \displaystyle \displaystyle \eta(x) = \left(1-2^{1-x}\right) \zeta(x)$ twice?
 
  • #3
Prometheus said:
Isn't it just a matter of applying the product rule on $ \displaystyle \displaystyle \eta(x) = \left(1-2^{1-x}\right) \zeta(x)$ twice?

Thanks for taking part, Prometheus! :D

More -->

Yes, you're absolutely correct. The idea of the problem was to, potentially, encourage people who're less familiar with the functional relation you cited to develop it for themselves, then differentiate it.
 

FAQ: An almost elementary differentiation problem....

What is "An almost elementary differentiation problem"?

"An almost elementary differentiation problem" refers to a mathematical problem that involves finding the derivative of a function using basic principles of differentiation, but may require some additional steps or techniques to solve.

Why is it called "almost elementary"?

It is called "almost elementary" because the problem can be solved using basic principles of differentiation, but may also require some additional steps or techniques that go beyond what is typically considered "elementary" in mathematics.

What makes "An almost elementary differentiation problem" challenging?

This type of differentiation problem can be challenging because it may require a combination of different rules and techniques, as well as a deeper understanding of the concepts behind differentiation. It may also involve complex functions or expressions that need to be simplified before applying the rules of differentiation.

How can one approach solving "An almost elementary differentiation problem"?

The best approach to solving this type of problem is to start by identifying the function and determining which differentiation rule(s) can be applied. Next, simplify the function as much as possible and then apply the chosen rule(s). If necessary, additional techniques such as the chain rule or product rule may need to be used. Finally, check your answer and simplify if necessary.

What are some tips for solving "An almost elementary differentiation problem"?

Some tips for solving this type of problem include practicing differentiating various types of functions, understanding the basic rules of differentiation, and being familiar with additional techniques such as the chain rule and product rule. It is also helpful to carefully read and understand the problem before attempting to solve it, and to double check your work and simplify your final answer.

Similar threads

Replies
4
Views
2K
Replies
5
Views
3K
Replies
7
Views
2K
Replies
1
Views
1K
Replies
5
Views
1K
Replies
2
Views
1K
Back
Top