- #1
Safinaz
- 260
- 8
Hi all,
In former threads, namely:
"Color factors of color -- octet scalars",
and
"The double line notation and the adjoint representation"
I were asking about the difference between the interaction vertices among:
* three gluons (GGG), as in SM,
* three colored octet scalars, call ## S = S^A T^A ##, where ## T^A ## are the ## SU_C(3)## generators, and A=1,..,8,
* GSS.Let me summarize the answer here:
In SM, the interactions between three gluons comes from the Lagrangian term;
$$ \mathcal{L} = F_{\mu \nu} F^{\mu\nu}, $$
where ## F_{\mu \nu} ## is the YM field strength, given by
$$ F_{\mu\nu} = \partial_{[\mu} A_{\nu]} + i g [ A_\mu, A_\nu], $$
So that GGG vertex comes from ## ig \text{Tr}(\partial_\mu A_\nu [ A^\mu, A^\nu]) \sim \text{Tr}(T_A [T_B,T_C]) \sim g f_{ABC} . ##
The interactions between three coloured octet fields (i.e. in the adjoint representation as gluons), is given by the interaction term:
\begin{equation*}
\begin{split}
\textrm{Tr} (S^A S^B S^C) &= \text{Tr} (T^A T^B T^C) S^A S^B S^C
\\& = \frac{1}{4} (d^{ABC} + i f^{ABC} ) S^A S^B S^C \sim d^{ABC}~~ S^A S^B S^C .
\end{split}
\end{equation*}
The term includes ## f^{ABC} ## has vanished because ## f^{ABC} ## is a totally symmetric tensor times a symmetric product.
The interactions between gluons and octet scalars come from the covariant derivative:
$$ \mathcal{L}_S = D^\mu S^\dagger D_\mu S, $$
\begin{equation*}
\begin{split}
( D_\mu S) ^A & = \partial_\mu S^A - i g A_{\mu B} (T_B)^{AC} S^C
\\ &= \partial_\mu S^A + g A_{\mu B} f_{ABC} S^C.
\end{split}
\end{equation*}
So that ## G_A S_B S_C ## vertex ## \sim f_{ABC} ##.
Where in the adjoint representation ## (T_{adj}^a) = -i f^{abc}##
A useful reference for that is of course:
An Introduction To Quantum Field Theory (Frontiers in Physics) (Michael E. Peskin, Dan V. Schroeder), Ch:15,
Hopefully that's useful for you and thanks for the advisors who helped me, fzero & samalkaiat
:)
S
[PLAIN]https://www.physicsforums.com/members/samalkhaiat.35381/[/PLAIN]
In former threads, namely:
"Color factors of color -- octet scalars",
and
"The double line notation and the adjoint representation"
I were asking about the difference between the interaction vertices among:
* three gluons (GGG), as in SM,
* three colored octet scalars, call ## S = S^A T^A ##, where ## T^A ## are the ## SU_C(3)## generators, and A=1,..,8,
* GSS.Let me summarize the answer here:
In SM, the interactions between three gluons comes from the Lagrangian term;
$$ \mathcal{L} = F_{\mu \nu} F^{\mu\nu}, $$
where ## F_{\mu \nu} ## is the YM field strength, given by
$$ F_{\mu\nu} = \partial_{[\mu} A_{\nu]} + i g [ A_\mu, A_\nu], $$
So that GGG vertex comes from ## ig \text{Tr}(\partial_\mu A_\nu [ A^\mu, A^\nu]) \sim \text{Tr}(T_A [T_B,T_C]) \sim g f_{ABC} . ##
The interactions between three coloured octet fields (i.e. in the adjoint representation as gluons), is given by the interaction term:
\begin{equation*}
\begin{split}
\textrm{Tr} (S^A S^B S^C) &= \text{Tr} (T^A T^B T^C) S^A S^B S^C
\\& = \frac{1}{4} (d^{ABC} + i f^{ABC} ) S^A S^B S^C \sim d^{ABC}~~ S^A S^B S^C .
\end{split}
\end{equation*}
The term includes ## f^{ABC} ## has vanished because ## f^{ABC} ## is a totally symmetric tensor times a symmetric product.
The interactions between gluons and octet scalars come from the covariant derivative:
$$ \mathcal{L}_S = D^\mu S^\dagger D_\mu S, $$
\begin{equation*}
\begin{split}
( D_\mu S) ^A & = \partial_\mu S^A - i g A_{\mu B} (T_B)^{AC} S^C
\\ &= \partial_\mu S^A + g A_{\mu B} f_{ABC} S^C.
\end{split}
\end{equation*}
So that ## G_A S_B S_C ## vertex ## \sim f_{ABC} ##.
Where in the adjoint representation ## (T_{adj}^a) = -i f^{abc}##
A useful reference for that is of course:
An Introduction To Quantum Field Theory (Frontiers in Physics) (Michael E. Peskin, Dan V. Schroeder), Ch:15,
Hopefully that's useful for you and thanks for the advisors who helped me, fzero & samalkaiat
:)
S
[PLAIN]https://www.physicsforums.com/members/samalkhaiat.35381/[/PLAIN]
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