An expression for the vertical velocity as a function of time

[Physil]

A rocket of initial mass m0 is launched vertically upwards from the rest. The rocket burns fuel at the constant rate m', in such a way, that, after t seconds, the mass of the rocket is m0-m't. With a constant buoyancy T, the acceleration becomes equal to a=T/(m0-m't) -g. The atmospheric resistance can be neglected, and the gravitational accelereation ,g, is considered a constant for low-level flights. Deduce an expression for the vertical velocity v of the rocket, as a function of time t, before the fuel burns out completely.

 

[vanhees71]

What are your ideas about the problem?

 

[Mister T]

We're not here to solve physics problems for you. We're here to help YOU solve them. You have to make an effort towards a solution. If you need a hint to get started, acceleration is the time derivative of velocity.

 

[Physil]

We're not here to solve physics problems for you. We're here to help YOU solve them. You have to make an effort towards a solution. If you need a hint to get started, acceleration is the time derivative of velocity.

I'm sorry. I new here. That's exactly what I was thinking. I just don't know if I should use definite or indefinite integral.

 

[berkeman]

I'm sorry. I new here. That's exactly what I was thinking. I just don't know if I should use definite or indefinite integral.

Why would you use an indefinite integral? Does the integration have a starting point and stopping point?

 

[Mister T]

I just don't know if I should use definite or indefinite integral.

Try it both ways and see. It doesn't take that much time.