An object with mass m moving on x'x and Ep(x) = (1/2)*k*(x^2 - 4)^2

In summary, the equation for potential energy in this scenario is Ep(x) = (1/2)*k*(x^2 - 4)^2, where m is the mass of the object, k is the spring constant, and x is the displacement of the object from its equilibrium position. The mass of the object does not directly affect its potential energy in this scenario. The x'x coordinate system represents the position of the object along the x-axis, allowing us to track displacement and calculate potential energy at different positions. If the spring constant is doubled, the potential energy of the object would also double. This is because potential energy is directly proportional to the square of the spring constant. The potential energy of the object can be negative if
  • #1
Michael_0039
59
7
Homework Statement
An object with m mass moving on x'x and Ep(x) = (1/2)*k*(x^2 - 4)^2 . x is the position of the object and k>0 (constant)

The object starts with zero velocity from x0=1

1) V(max) = ? and X @ V(max)
2) Which is the position speed will be zero again ?
Relevant Equations
nil
Hi !

This is my try:

New Doc 2019-11-17 23.40.59_1.jpg


New Doc 2019-11-17 23.40.59_2.jpg
Is that correct ?

Thanks
 
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  • #2
Almost correct. All of your calculations are right, but you need to figure out which solutions for ##v=0## can actually happen. How much total energy would be required for the system to achieve ##x=0##? What would be the velocity at that point if the total energy is ##\frac 9 2 k##?
 
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  • #3
In addition to @tnich's observation, I have a minor comment. Your sketch is a little out of scale. Which two of the x positions 1, 2, √7 should be closest together?
 

FAQ: An object with mass m moving on x'x and Ep(x) = (1/2)*k*(x^2 - 4)^2

1. What is the significance of the mass and position of an object in the given equation?

The mass, represented by 'm', determines the inertia of the object and how it responds to external forces. The position, represented by 'x', dictates the potential energy of the object at a given point along the x-axis.

2. How does the value of k affect the energy of the system?

The value of k, representing the stiffness of the system, directly influences the potential energy of the object. A higher value of k results in a stiffer system and a higher potential energy, while a lower value of k results in a more flexible system and a lower potential energy.

3. Can you explain the physical meaning of Ep(x) in this equation?

Ep(x) represents the potential energy of the object at a specific position along the x-axis. It is a measure of the energy stored in the system due to the position of the object and the stiffness of the system.

4. How does the shape of the potential energy curve change as the object moves along the x-axis?

The potential energy curve is a parabola that opens upwards. As the object moves along the x-axis, the curve shifts along with it. The minimum point of the curve represents the equilibrium position of the object, where the potential energy is at its lowest.

5. Is this equation applicable to all objects with mass moving on the x-axis?

No, this equation is specifically for an object with mass m moving on the x-axis subject to a harmonic force. Other forces and systems may require different equations to accurately describe their motion and potential energy.

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