Analysing Non-Inverting Op-Amp Circuit: Questions & Answers

  • Thread starter Evales
  • Start date
  • Tags
    Op-amp
In summary: Thanks!In summary, the circuit diagram has a pair of resistors in parallel, a voltage source (S1), and an output. The gain and phase shift can be calculated by using Kirchoff's circuit laws.
  • #1
Evales
54
0
I'm supposed to be analysing this circuit to go with my lab report. However I haven't seen a circuit like this. First off I'm not sure what the symbol is on the top left resistor (15kΩ//1.2kΩ) means.

Secondly I'm used to doing inverting op amps and they generally don't have many/ any resistors attached to the side that doesn't have the voltage source. I'm curcious if and what effect the other resistors will have. I'm assuming there's some kind of feedback there, however I'm not sure how to connect the voltage source and the feedback.

Any help would be greatly appreciated. The circuit diagram is below.

R0f0e.png
 
Physics news on Phys.org
  • #2
The circuit is complete as shown. You don't add any more resistors. The 10k resistor is the feedback resistor. You connect your source to input S1 and take output at Out1.

15k // 1.2k is a pair of resistors in parallel, and is a method of providing a resistance of a special intermediate value when it's needed, that's all.
 
  • #3
Evales said:
I'm supposed to be analysing this circuit to go with my lab report. However I haven't seen a circuit like this. First off I'm not sure what the symbol is on the top left resistor (15kΩ//1.2kΩ) means.

Well, what did you actually do in your lab (I assume that you did the experiment if you are writing a report on it)? Did you maybe build 2 different versions of this circuit - one with a 15kΩ resistor and one with a 1.2kΩ resister?

Secondly I'm used to doing inverting op amps and they generally don't have many/ any resistors attached to the side that doesn't have the voltage source. I'm curcious if and what effect the other resistors will have. I'm assuming there's some kind of feedback there, however I'm not sure how to connect the voltage source and the feedback.

Any help would be greatly appreciated. The circuit diagram is below.

R0f0e.png

As always (when dealing with op amps), start with the Gain equation:

[tex]V_{\text{out}}=A(V_{+} - V_{-})[/tex]

Use Kirchoff's circuit laws to express [itex]V_{+}[/itex] and [itex]V_{-}[/itex] in terms of the resistors in your circuits, the output potential ([itex]V_{ \text{out} }[/itex]) ,and the input potential ([itex]S_{1}[/itex]?).
 
  • #4
Thanks to both of you for responding. The lab was just connecting a board with jumpers and using an oscilloscope to evaluate the gain and the phase shift.

So from what I've gathered:

The odd symbols for the resistors was two resistors in parallel. And thanks especially for the tip to start with A(V--V+), our lecturers and tutors just run ahead and do each circuit in the quickest way possible, so I'm left trying to think of the best way to look at a problem. I'm not great with analysis when there's heaps of different ways of doing it. I get overloaded everytime I look at a problem trying to think of the best way to do it haha.

Thanks again!
 
  • #5
This is an amplifier with negative feedback so you can assume that V at the + input equals V at the - input.
If you know the voltage S1 can you see how to work out the output voltage to make V+ =V- ?.
Small tip ...The 10k from S1 to ground is not important in the calculation, do you know why?
 

FAQ: Analysing Non-Inverting Op-Amp Circuit: Questions & Answers

What is a non-inverting op-amp circuit?

A non-inverting op-amp circuit is a type of electronic circuit that uses an operational amplifier (op-amp) to amplify a signal without inverting its polarity. This means that the output signal will have the same polarity as the input signal.

How does a non-inverting op-amp circuit work?

In a non-inverting op-amp circuit, the input signal is connected to the non-inverting input of the op-amp, while the inverting input is connected to ground. The op-amp amplifies the difference between the two inputs and produces an output signal that is proportional to the input signal. The gain of the circuit is determined by the ratio of the feedback resistor to the input resistor.

What is the purpose of using a non-inverting op-amp circuit?

A non-inverting op-amp circuit is commonly used to amplify signals without changing their polarity. It is also used to provide buffering and impedance matching between different components in a circuit. Additionally, it can be used as a voltage follower to isolate a load from the signal source.

How is the gain of a non-inverting op-amp circuit calculated?

The gain of a non-inverting op-amp circuit is calculated using the formula: Gain = 1 + (Rf/Rin), where Rf is the feedback resistor and Rin is the input resistor. This means that the gain is directly proportional to the ratio of these two resistors. For example, if Rf = 10kΩ and Rin = 1kΩ, the gain would be 11 (1 + 10).

What are some common applications of non-inverting op-amp circuits?

Some common applications of non-inverting op-amp circuits include audio amplifiers, signal conditioning, active filters, and voltage regulators. They are also used in instrumentation and measurement circuits, as well as in electronic devices such as speakers, microphones, and sensors.

Similar threads

Replies
21
Views
2K
Replies
13
Views
2K
Replies
4
Views
2K
Replies
6
Views
2K
Replies
0
Views
2K
Back
Top