- #1
Physgeek64
- 247
- 11
In our complex variables course we were told that an analytic function of an analytic function is itself analytic. i.e. For ##h(z)=g(f(z))## ##h(z)## is analytic.
I was wondering is this is just a fact, or if it is possible to prove this statement. I did some googling and the best response I could find was :
##h'(z)= g'(f(z)) f'(z)##, which for ##f'(z)## and ##g'(f(z))## not equal to zero, describes an analytic function.. But I'm afraid this doesn't seem like much of a proof to me.
Many thanks :)
I was wondering is this is just a fact, or if it is possible to prove this statement. I did some googling and the best response I could find was :
##h'(z)= g'(f(z)) f'(z)##, which for ##f'(z)## and ##g'(f(z))## not equal to zero, describes an analytic function.. But I'm afraid this doesn't seem like much of a proof to me.
Many thanks :)