- #1
galaxy_twirl
- 137
- 1
Homework Statement
In the Figure Q1 (c), the switch S was closed for very long time before it is opened at time t = 0. Find the value of vC(t) and iL(t) at t = 0+ c L i.e. immediately after the switch was opened.
Homework Equations
V = IR
The Attempt at a Solution
From DC steady state, we know that C acts as an open circuit while L acts as a short wire, hence, we will have:
Current in circuit = 20 / (10+10) = 1A
vC(t) is thus 20 - (10*1) = 10V.
However, for iL(t), I am a bit confused, because since this is a short wire, will the 2A current affect the current in this wire? This is because my answer is 1A, however, when I simulate this circuit in LTSpice, it gave me an answer of 3A, which is a bit puzzling. The direction of current would be different, and thus, even if the 2A current source affects the current in the inductor (which is a short), it should be 1-2 = -1A right?
Thanks for any assistance rendered! :D