- #1
Maor Hadad
- 9
- 0
Homework Statement
[tex]
\frac{d}{dt}\left(\frac{\dot{q}}{\sqrt{1+\left(\dot{q}\right)^{2}}}\right)=0\Rightarrow\frac{\dot{q}}{\sqrt{1+\left(\dot{q}\right)^{2}}}=const\Rightarrow\dot{q}=A\Rightarrow q=At+B
[/tex]
Homework Equations
Why it ok to say that:
[tex]
\frac{\dot{q}}{\sqrt{1+\left(\dot{q}\right)^{2}}}=const\Rightarrow\dot{q}=A
[/tex]
The Attempt at a Solution
[tex]
\left(\frac{\dot{q}}{const}\right)^{2}-\dot{q}-1=0\Rightarrow?
[/tex]