Angle of elevation and depression problems

In summary, in the first conversation, Prof Micheal determines the height of the clock tower by using the angles of elevation at two different distances from the tower. In the second conversation, an engineer uses the cosine rule to find the length of a tunnel given two known distances and an angle.
  • #1
Jerome1
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(1) Prof micheal walks towards the university clock tower and decides to find the height of the clock above ground. He determines the angle of elevation to be 30 degrees and after proceeding an additional 60m towards the base of the tower, he finds the angle of elevation to be 40 degrees. What is the height of the clock tower

(2) An engineer who is to dig a tunnel through a small mountain wish to deternine the length of the tunnel. Point X and Y are chosen as the end points of the tunnel, then a point Z is chosen from which the distances to X and Y are found to be 19km and 23km respectively. If angle XZY measures 48 degrees, find the length of the tunnel.
 
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  • #2
If you draw out 1, you'll see two right angle triangles, one with an angle of 30 degrees with a distance of x metres from the clock tower, the other with an angle of 40 degrees with a distance of (x - 60) metres from the clock tower. Obviously both have a height of h metres, the clock tower's height. From there:

$\displaystyle \begin{align*} \tan{ \left( 30^{\circ} \right) } &= \frac{h}{x} \\ \frac{1}{\sqrt{3}} &= \frac{h}{x} \\ \frac{x}{\sqrt{3}} &= h \\ x &= h\sqrt{3} \end{align*}$

and also

$\displaystyle \begin{align*} \tan{ \left( 40^{\circ} \right) } &= \frac{h}{x - 60} \\ \tan{ \left( 40^{\circ} \right) } &= \frac{h}{h\sqrt{3} - 60} \\ \left( h\sqrt{3} - 60 \right) \tan{ \left( 40^{\circ} \right) } &= h \\ h\sqrt{3} \tan{ \left( 40^{\circ} \right) } - 60\tan{ \left( 40^{\circ} \right) } &= h \\ h\sqrt{3} \tan{ \left( 40^{\circ} \right) } - h &= 60\tan{ \left( 40^{\circ} \right) } \\ h \left[ \sqrt{3} \tan{ \left( 40^{\circ} \right) } - 1 \right] &= 60\tan{ \left( 40^{\circ} \right) } \\ h &= \frac{60\tan{ \left( 40^{\circ} \right) } }{\sqrt{3}\tan{ \left( 40^{\circ} \right) } - 1} \end{align*}$

Now put this into your calculator to get your decimal approximation :)

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Jerome said:
(1) Prof micheal walks towards the university clock tower and decides to find the height of the clock above ground. He determines the angle of elevation to be 30 degrees and after proceeding an additional 60m towards the base of the tower, he finds the angle of elevation to be 40 degrees. What is the height of the clock tower

(2) An engineer who is to dig a tunnel through a small mountain wish to deternine the length of the tunnel. Point X and Y are chosen as the end points of the tunnel, then a point Z is chosen from which the distances to X and Y are found to be 19km and 23km respectively. If angle XZY measures 48 degrees, find the length of the tunnel.

For the second, draw it out and you'll see you have a triangle with two known lengths and the angle between them known. You can use the cosine rule to evaluate the third length (which is the distance XY, the length of the tunnel).
 

FAQ: Angle of elevation and depression problems

What is the difference between angle of elevation and angle of depression?

Angle of elevation refers to the angle formed between a horizontal line and a line of sight pointing upwards. On the other hand, angle of depression refers to the angle formed between a horizontal line and a line of sight pointing downwards.

How do you solve angle of elevation and depression problems?

To solve angle of elevation and depression problems, you can use trigonometric ratios such as tangent, sine, and cosine. You can also use the properties of parallel lines and transversals to determine the angles.

What are some real-life applications of angle of elevation and depression?

Angle of elevation and depression are commonly used in navigation, surveying, and engineering to calculate heights and distances. They are also used in sports such as golf and archery to determine the angle at which an object needs to be launched to reach a specific target.

How can I remember which trigonometric ratio to use for angle of elevation and depression problems?

A helpful mnemonic to remember is "SOH CAH TOA". Sine is opposite over hypotenuse, cosine is adjacent over hypotenuse, and tangent is opposite over adjacent. Use the appropriate ratio based on the given information in the problem.

Can angle of elevation and depression problems have more than one solution?

Yes, angle of elevation and depression problems can have more than one solution. This can occur when there are multiple triangles that satisfy the given conditions, or when the angle measurements are not precise. It is important to carefully read the problem and draw accurate diagrams to determine the correct solution.

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