Angle of twist and Shear stress in a shaft

In summary, the numerical values are correct this time, however, the maximum shear stress near the surface of the shaft should be 0.229 MPa (millions of Pascals) rather than GPa (billions of Pascals).
  • #1
Ben_Walker1978
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Homework Statement
Find the Angle of twist and Shear stress in a shaft
Relevant Equations
Angle of twist and Shear stress in a shaft
Hello,

I have attempted the question below.

I think i have correctly completed the question.

Could anyone see if i have gone wrong?

As trying to learn this.

I am just worried about the units m to mm. Also the answer being correct, 917.6Gpa. I was unsure what units to use on the answer.

Question:

Part 3 ii).jpg
Answer:

Part 3 ii) - Answer.jpg


Any help much appreciated.
 
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  • #2
It is not shown in the diagram, but the 225 N is a force, not a torque, and it acts tangent to the circumference of the shaft at its free end. What is the Torque caused by it? Then watch your conversion factors, there's a lot of zeros when using SI units.
 
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  • #3
So this whole calculation is wrong? Do i convert force to Torque? Thanks for replying to help
 
  • #4
If you determine the correct torque and use it in your equations and check your math, and units, you will have it right!
 
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  • #5
Ok.

So i have:

T = r x F

T = 25mm x 2.5N

T = 5,625Nmm

Is this correct calculations for torque?

So i can then place in my calculations and try complete the calculation.

Thank you.
 
  • #6
Yes, That's T= (25)(225) = 5,625 N.mm
 
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  • #7
Thank you.

I have re calculated.

Is my answer now correct?

Conversion factors is where i struggle.

Part 3 a) - b).png
 
  • #8
Ben_Walker1978 said:
Conversion factors is where i struggle.
That’s for sure. Your answer for torsional shear stress is off by a factor of one million. Don’t feel bad, I’m from the US and I seldom use metric , so it confuses the living daylights out of me. Once I ordered 1/4 inch thick plate from China and they offered me 6mm instead. It took me awhile to convince myself that it was more or less the same. Except a lot cheaper than steel from the US mills.

And you didn’t correct your angle of twist!

I hope you get it right next time, because it takes me forever to do the math because of all those zeroes and mega and giga stuff. 😷
 
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  • #9
I thought angle of twist was correct. Not sure where i have gone wrong there?

I was have another attempt and post.

I hope i get it right this time too!

Thank you for your help. Very much appreciated.
 
  • #10
My attempt with new calculations.

I think this is now correct.

If not where am i going wrong?

Part 3 a) - b).png
 
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  • #11
Ben_Walker1978 said:
My attempt with new calculations.

I think this is now correct.

If not where am i going wrong?

The numerical values are correct this time, however, the maximum shear stress near the surface of the shaft should be 0.229 MPa (millions of Pascals) rather than GPa (billions of Pascals).

Ben_Walker1978 said:
Conversion factors is where i struggle.
My suggestion is that, before attempting any calculation, you convert all the given units to base and derived SI units.
Then, convert prefixes (like giga en GPa) to scientific notation.
By doing so, you very much simplify your calculations, since you only have integer powers of ten to deal with.

Please, see:
https://en.wikipedia.org/wiki/International_System_of_Units

https://en.wikipedia.org/wiki/Scientific_notation

Regarding the units, should should also keep track of the way they get combined in the several operations.
By doing so, you could catch errors at the end.

For example, you could have noted that your answer to a) in post #1 was not correct, unit-wise, as you entered N for torque rather than N-m and ended with an additional m that could not be cancelled.

Take a look at these examples of similar calculations (which use higher values of torque):
https://www.engineeringtoolbox.com/torsion-shafts-d_947.html

:cool:
 
Last edited:
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  • #12
Lnewqban said:
The numerical values are correct this time, however, the maximum shear stress near the surface of the shaft should be 0.229 MPa (millions of Pascals) rather than GPa (billions of Pascals).My suggestion is that, before attempting any calculation, you convert all the given units to base and derived SI units.
Then, convert prefixes (like giga en GPa) to scientific notation.
By doing so, you very much simplify your calculations, since you only have integer powers of ten to deal with.

Please, see:
https://en.wikipedia.org/wiki/International_System_of_Units

https://en.wikipedia.org/wiki/Scientific_notation

Regarding the units, should should also keep track of the way they get combined in the several operations.
By doing so, you could catch errors at the end.

For example, you could have noted that your answer to a) in post #1 was not correct, unit-wise, as you entered N for torque rather than N-m and ended with an additional m that could not be cancelled.

Take a look at these examples of similar calculations (which use higher values of torque):
https://www.engineeringtoolbox.com/torsion-shafts-d_947.html

:cool:
Thank you for this.

The links will help me.

I am going to attempt another question to try and get use to doing the calculations.

So i have changed to Mpa.

So this is now correct? So i can use to help solve another question.

Your help is very much appreciated.

Part 3 a) - b).png
 
  • #13
Yes, I believe all is correct now.
You are very welcome, Ben. :smile:
 

FAQ: Angle of twist and Shear stress in a shaft

What is the angle of twist in a shaft?

The angle of twist in a shaft refers to the amount of rotation or deformation that occurs along the length of the shaft due to the application of a twisting or shearing force.

How is the angle of twist calculated?

The angle of twist can be calculated using the formula: θ = TL/GJ, where θ is the angle of twist, T is the applied torque, L is the length of the shaft, G is the shear modulus of the material, and J is the polar moment of inertia of the shaft.

What is shear stress in a shaft?

Shear stress in a shaft is the force per unit area that is applied parallel to the cross-sectional area of the shaft. It is caused by the shearing or twisting force applied to the shaft.

How is shear stress calculated in a shaft?

Shear stress in a shaft can be calculated using the formula: τ = Tr/J, where τ is the shear stress, T is the applied torque, r is the radius of the shaft, and J is the polar moment of inertia of the shaft.

What are the factors that affect the angle of twist and shear stress in a shaft?

The angle of twist and shear stress in a shaft are affected by the material properties of the shaft, the applied torque, the length and diameter of the shaft, and the shape of the cross-section of the shaft.

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