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dlp211
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Homework Statement
A physical pendulum consists of a small 1.5kg mass at the bottom end of a uniform 1.00m long 1.5kg stick swinging about its upper end. The moment of inertia of the pendulum about its upper end is 2.00kg*m^2. What is the angular frequency
Homework Equations
sqrt(mgd/I)=w
I = I(cm)+md^2 = I = (1/3)(1.5)(1^2)+ (1.5)(d^2) = 2
The Attempt at a Solution
m = 1.5+1.5
g = 9.81
d = 1
I = 2
w = sqrt([3*9.81*1]/2) = 3.83 rad/s
According to my solutions manual this is wrong and the correct answer is 3.32 rad/s and somehow d = .75. I don't know how they calculated that, can anyone help?