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Cfem
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I only have one more attempt on this question before I lost all of the points, so detailed help would be much appreciated. I understand everything conceptually (I think), but I don't know where I went wrong.
A 2.3 kg wood block hangs from the bottom of a 1.3 kg, 1.3 meter long rod. The block and rod form a pendulum that swings on a frictionless pivot at the top end of the rod. A 12 g bullet is fired into the block, where it sticks, causing the pendulum to swing out to a 35 degree angle.
Conservation of angular momentum
Conservation of energy
Moment of Inertia
mb = .012 kg
mB = 2.3 kg
mR = 1.3 kg
L = 1.3 m
r = .65m
vi = ?
-Conservation of Angular momentum:
Ai = Af
Ai = (mb)(vi)(L) = IT(w) = Af
Where w is the final angular velocity
Where IT is the total moment of inertia of the system. Given by:
(1/3)((mR)(r)2 + (mb + mB)(L2)
So,
1: w =([mb * vi * L)/IT
-Conservation of Energy
KE = Change in PE
KE = (1/2)(IT)w2
Change in PE, treating initial position of the pendulum as PE = 0:
PE = mT * g * h
mT is the sum of the masses
Where h is the change in height, denoted by the change in the center of mass as the pendulum rotates:
center of mass = c = (mR * L + (mB + mb)*r)/mT
h = c - c*cos(35)
Equating KE and PE, then solving for w:
w2 = (mT * g * h)*2/IT
So w is the square root of all that mess.
Equating the above equation with 1 and solving for vi
vi = (IT* sqrt{ (mT * g * h)*2 / IT }) / ((mb)(L))
Which gives me something like 441. I'm really frustrated with this and I'm not sure what I did wrong. Thanks in advance.
Homework Statement
A 2.3 kg wood block hangs from the bottom of a 1.3 kg, 1.3 meter long rod. The block and rod form a pendulum that swings on a frictionless pivot at the top end of the rod. A 12 g bullet is fired into the block, where it sticks, causing the pendulum to swing out to a 35 degree angle.
Homework Equations
Conservation of angular momentum
Conservation of energy
Moment of Inertia
The Attempt at a Solution
mb = .012 kg
mB = 2.3 kg
mR = 1.3 kg
L = 1.3 m
r = .65m
vi = ?
-Conservation of Angular momentum:
Ai = Af
Ai = (mb)(vi)(L) = IT(w) = Af
Where w is the final angular velocity
Where IT is the total moment of inertia of the system. Given by:
(1/3)((mR)(r)2 + (mb + mB)(L2)
So,
1: w =([mb * vi * L)/IT
-Conservation of Energy
KE = Change in PE
KE = (1/2)(IT)w2
Change in PE, treating initial position of the pendulum as PE = 0:
PE = mT * g * h
mT is the sum of the masses
Where h is the change in height, denoted by the change in the center of mass as the pendulum rotates:
center of mass = c = (mR * L + (mB + mb)*r)/mT
h = c - c*cos(35)
Equating KE and PE, then solving for w:
w2 = (mT * g * h)*2/IT
So w is the square root of all that mess.
Equating the above equation with 1 and solving for vi
vi = (IT* sqrt{ (mT * g * h)*2 / IT }) / ((mb)(L))
Which gives me something like 441. I'm really frustrated with this and I'm not sure what I did wrong. Thanks in advance.