Angular momentum for third electron of Lithium

[xiphoid]

Homework Statement

For the third electron of Lithium atom moving in its permissible orbit, the values of angular momentum and the energy are?

Homework Equations

E= -2π²e⁴mZ²/n²h²
Third electron is in the second orbit

The Attempt at a Solution

The value for energy should be -9∏²e⁴m/2h²
Correct me if i am wrong for the above answer,
Angular momentum= nh/2∏
So its value should h/∏

Am i right?

 

[AGNuke]

These equations are only applicable for Li²⁺ ion, as Bohr Model are only applicable for Single electron species.

 

[xiphoid]

So, what do you think, my answer is right?

These equations are only applicable for Li²⁺ ion, as Bohr Model are only applicable for Single electron species.

 

[AGNuke]

Can't say about Li "atom". Talk about Li "ion". Then your answer may be right, simple substitution.

Well, owing to the fact you asked multiple questions, I guess you are studying Bohr Model.

 

[DeeNos]

I cannot confirm the accuracy of your calculations without knowing the specific values of the variables in the equations. However, your approach seems to be correct. The energy of the third electron in the second orbit of a Lithium atom can be calculated using the equation E= -2π2e4mZ2/n2h2, where e is the charge of an electron, m is the mass of an electron, Z is the atomic number of Lithium (3), and n is the orbit number (2). Similarly, the angular momentum of the third electron can be calculated using the equation L= nh/2π, where n is the orbit number and h is Planck's constant. Without knowing the specific values of the variables, I cannot confirm the exact values for energy and angular momentum, but your approach seems to be correct.