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hussey1
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Hi all ,
I'm new here, studying computer aided product design and in my second year. We do a lot of physics and maths. I am stuck on a current question, probably not too hard but I am struggling to know what to do and the lecturers notes are not very helpful.
Calculate the maximum speed in km/h at which a train may travel around a bend of 100m radius if the maximum centripetal acceleration must not exceed 0.1g in order to maintain passenger comfort.
Centripetal acceleration = V^2 / r
2 x Pi x r
radian to degree = X x 180/pi
Attempted using above equations and tried different methods the closest I got to the answer is:
2 x pi x r
= 2 x pi x 100
= 628 = 0.628km
0.628 x 180/pie
=35.98
I have the answer but just can't quite get it, the answer is: 35.66 km/h
Other methods I tried are here (I know they are not correct, but I tried anyway):
0.1g= V^2 / r
0.1g = V^2 / 100m
V^2 = 0.1g x 100m
V^2 = 10 (g/m?)
v = Square root of 10
V = 3.16
I also used the same as above but put this in the equation 0.1 x 9.81 = 0.981 and I got 0.99
Many thanks in advance
Ollie
I'm new here, studying computer aided product design and in my second year. We do a lot of physics and maths. I am stuck on a current question, probably not too hard but I am struggling to know what to do and the lecturers notes are not very helpful.
Homework Statement
Calculate the maximum speed in km/h at which a train may travel around a bend of 100m radius if the maximum centripetal acceleration must not exceed 0.1g in order to maintain passenger comfort.
Homework Equations
Centripetal acceleration = V^2 / r
2 x Pi x r
radian to degree = X x 180/pi
The Attempt at a Solution
Attempted using above equations and tried different methods the closest I got to the answer is:
2 x pi x r
= 2 x pi x 100
= 628 = 0.628km
0.628 x 180/pie
=35.98
I have the answer but just can't quite get it, the answer is: 35.66 km/h
Other methods I tried are here (I know they are not correct, but I tried anyway):
0.1g= V^2 / r
0.1g = V^2 / 100m
V^2 = 0.1g x 100m
V^2 = 10 (g/m?)
v = Square root of 10
V = 3.16
I also used the same as above but put this in the equation 0.1 x 9.81 = 0.981 and I got 0.99
Many thanks in advance
Ollie
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