- #1
agross
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I have computed angular speed, centripetal acceleration, and torque for a uniform circular motion.
What is the tangential acceleration?
I am leaning towards tangential a = r(alpha) where alpha is d(omega)/dt.
since I have calculated omega and a = dv/dt - I think its safe to
say that as dt cancels dv = r d(omega) = a tangential?
Any tips?
What is the tangential acceleration?
I am leaning towards tangential a = r(alpha) where alpha is d(omega)/dt.
since I have calculated omega and a = dv/dt - I think its safe to
say that as dt cancels dv = r d(omega) = a tangential?
Any tips?