Another capacitor Laplace transform problem

In summary, the conversation discusses using the Laplace transform to solve a two capacitor problem involving discharging and charging capacitors through a resistor. The individual equations for the capacitors are coupled with the same current, leading to a system of equations that can be solved with initial conditions. The conversation also mentions the importance of correctly including initial conditions when using the Laplace transform.
  • #1
bitrex
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I'm trying to use the Laplace transform to work out another capacitor problem, the voltage as a function of time on a capacitor that's discharging into another capacitor through a resistor. It's the classic two capacitor problem, but I'd like to actually find an expression for the voltage as a function of time across the capacitor that's discharging and the capacitor that's charging. I've tried setting up a coupled differential equation, like this:

[tex]\frac{Vc_1 - Vc_2}{R} = C_2\frac{dV_{C2}}{dt}[/tex]
[tex]\frac{Vc_2 - Vc_1}{R} = C_1\frac{dV_{C1}}{dt}[/tex]

but of course when I take the Laplace transform and try to solve it algebraically I get a system of equations the equivalent of something like A = 5B and B = 4A, which is useless. Any tips on a better way of setting this up would be appreciated.
 
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  • #2
I don't know about the laplace transform, but the current in the circuit is the same. so the right side of both equations is equal. integrate both sides and plug in any initial conditions? the problem maybe has to do with the ratio of capacitances.
 
  • #3
The only way you could get an homogenous system of equations is by letting the initial conditions (voltage of the capacitors) be zero, then it's not a surprise you will get a trivial solutions.

Use

[tex]L(\frac{d}{dt}y)(s)=sY(s)-y(0)[/tex]
 
  • #4
Yes, that's what went wrong. I forgot to put in the initial conditions properly! Thank you.
 

FAQ: Another capacitor Laplace transform problem

What is a capacitor Laplace transform problem?

A capacitor Laplace transform problem involves using the Laplace transform to analyze a circuit containing capacitors. The Laplace transform is a mathematical tool used to convert time-domain functions into frequency-domain functions, making it useful for analyzing circuits with varying inputs over time.

How is the Laplace transform used in solving capacitor problems?

The Laplace transform is used to convert the differential equations that describe the behavior of capacitors in a circuit into algebraic equations that can be easily solved. This allows for a more efficient and systematic approach to analyzing and solving capacitor problems.

What are the benefits of using the Laplace transform for capacitor problems?

The Laplace transform provides a more comprehensive analysis of capacitor problems compared to traditional methods. It allows for the analysis of circuits with varying inputs and initial conditions, and it can also handle complex circuits with multiple capacitors and other components. Additionally, the Laplace transform simplifies the solution process and reduces the amount of mathematical manipulation needed.

Are there any limitations to using the Laplace transform for capacitor problems?

While the Laplace transform is a powerful tool for analyzing and solving capacitor problems, it does have some limitations. It assumes that the circuit is in a steady state and that the components are linear, which may not always be the case in practical circuits. Additionally, the Laplace transform may not be as intuitive for beginners and may require some practice to fully understand and apply.

Can the Laplace transform be applied to other types of circuits besides those with capacitors?

Yes, the Laplace transform can be applied to a variety of circuits with different components, including resistors, inductors, and current or voltage sources. It is a versatile tool in circuit analysis and is commonly used in various fields of engineering and science.

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