Answer Gas Container Volumes: Find Difference at 273K and 760mmHg

[kennylcc001]

Two gas containers with volume of 100cm3 and 1000cm3 respectively are connected by a tube of negligible volume, and contain air at a pressure of 1000mm mercury. If the temperature of both vessels is originally at 273K. and the temperature of the smaller container is raised to 373K.

How much air will pass through the connecting tube? (Give your answer in cm3 at 273K and 760mmHg)





Well, i feel that this Q is weird.
I know that the true solution is to find the decrease of mole in 100cm3.
But i found sth weird. If i use P1V1/T1 = P2V2/T2,
and use V2-V1, the answer is the same. (Approximately 33cm3)
May i know whether the second solution works?

 

[AvroArrow]

Yes, the second solution works. Under certain conditions, the equation P1V1/T1 = P2V2/T2 can be used to calculate the amount of air that will pass through a connecting tube. In this particular case, the pressure and temperature of both vessels are known, so it is possible to use this equation to calculate the amount of air that will pass through the connecting tube.

 

[kyle8921]

I would say that both solutions can work, but they may not give the same exact answer due to potential rounding errors or other factors. The first solution of finding the decrease in moles is the more accurate and precise method, as it takes into account the change in temperature and the ideal gas law. The second solution of using the difference in volumes may give a close approximation, but it does not take into account the change in temperature and may not be as accurate. It would be best to use the first solution for a more accurate result.