Anti-Derivatives with Substitution: Solving x^2(1-x)^8dx

In summary, Homework StatementThe student attempted to solve a derivative problem on a forum, but got lost. They then contacted the teacher for help, and he was able to guide them to the correct solution.
  • #1
A_Munk3y
72
0

Homework Statement


Well, i didn't know how to do anti-derivatives on this forum so i just did it on paint :)
Anyways, here is the problem and solution i tried.
Let me know if i did anything wrong, or if i even did anything right...
Thanks a lot!

i have to find the anti derivative of : x2(1-x)8dx

The Attempt at a Solution


vwtphe.jpg
 
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  • #2
Hey a Munk3y, it looks good exceot for the multiplication of [itex] (1-u)^2u^8[/itex]. try expanding the squared term first...
 
  • #3
yea, i thought that was wrong... I've always sucked at doing this..

so (1-u)2=u2-2u+1
then, u8(u2-2u+1) right?

would it be u8-2u9+u10
 
  • #4
Thats absolutely right. Alot of people don't even see making the substitution for x afterwards, they get stuck after the u-substitution.
 
  • #5
ok thanks :biggrin:, but now I'm a little lost on what to do now with this...
i tried to change it since i have a new equation but i think I'm doing something wrong.
either I'm doing the signs wrong, or something else, but it just doesn't seem right

here is what i got
20a2byp.jpg
 
Last edited:
  • #6
No that is fine! You can simplify the -2/10 to -1/5, and rewrite the terms in order of decreasing exponents, but only the evilest of teachers would expect you to expand those terms!
 
  • #7
Also, I commend you on using paint. That takes dedication!
 
  • #8
heh... yea, paint is a pain :cry:, but it's still easier than trying to figure out how to do it on this forum
and my teacher told us we don't have to simplify, so I'm good :Done last thing to be sure... :P I'm right in that only the 2/10(1-x)10 is negative? I thought i had messed that one up :shy:
 
  • #9
Actually all the signs are bacwards, you lost the negative sign right after your first equal sign.
 
  • #10
You get du = -dx. This implies that -du = dx as well. The intermediate step in your solution would be [itex] - \int u^8 - 2u^9 + u^{10} du = \int - u^8 + 2u^9 - u^{10} du [/itex] and you would break up the integrals from there. LaTex isn't so bad to learn! I guarantee that it takes less time than paint =)
 
  • #11
yea, i thought i had done something wrong
so is this right now?
suynbs.jpg
 
  • #12
You got it!
 
  • #13
YEA! :)
thanks so much for the help!
I reaaaaaaaally appreciate it.
 

FAQ: Anti-Derivatives with Substitution: Solving x^2(1-x)^8dx

What is Anti-deriv using substitution?

Anti-deriv using substitution is a method used in calculus to find the integral of a function by substituting a variable in the integrand with a new variable and then solving the resulting integral using basic integration rules.

Why is Anti-deriv using substitution useful?

This method is useful because it allows us to solve integrals that would otherwise be difficult or impossible to solve using basic integration rules. It also provides an alternate method for solving integrals and can help with simplifying complicated functions.

How do you know when to use Anti-deriv using substitution?

You should use Anti-deriv using substitution when the integrand contains a function and its derivative. This is because the substitution of a variable will allow you to simplify the integrand and make it easier to solve.

What are the steps for using Anti-deriv using substitution?

The steps for using Anti-deriv using substitution are:
1. Identify a function and its derivative in the integrand
2. Choose an appropriate substitution (usually the derivative of the function)
3. Rewrite the integrand in terms of the new variable
4. Solve the resulting integral using basic integration rules
5. Substitute the original variable back into the solution

Can Anti-deriv using substitution be used for all integrals?

No, Anti-deriv using substitution cannot be used for all integrals. It is most effective for integrals that contain a function and its derivative. In some cases, other methods such as integration by parts may be more suitable.

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