MHB Application of existence and uniqueness theorem

Click For Summary
The discussion focuses on applying the existence and uniqueness theorem to the initial value problem (IVP) defined by the differential equation y' = 4x^3y^3 with the initial condition y(1) = 0. To determine the existence and uniqueness of solutions, one must check if the function f(x, y) = 4x^3y^3 is differentiable and if its partial derivative with respect to y is continuous. The participants clarify that the checks should be performed on the function f itself, not on a potential solution. Since f is differentiable and its partial derivative is continuous, the theorem concludes that there is a unique solution to the IVP. Thus, the existence and uniqueness theorem confirms that a single solution exists for the given initial condition.
find_the_fun
Messages
147
Reaction score
0
Given the differential equation [math]y'=4x^3y^3[/math] with initial condition [math]y(1)=0[/math]determine what the existence and uniqueness theorem can conclude about the IVP.

I know the Existence and Uniquness theorem has two parts 1)check to see if the function is differentiable and 2)check to see if $$\frac{\partial f}{\partial y}$$ is continious. If they both are true you can condlude there is only one solution (a unique solution). If not, then you can't conclude anything.

My problem is I don't understand which function I should be checking. Should I be checking the differential equation it self, or do I first need to solve and and then check the (a) solution?
 
Physics news on Phys.org
find_the_fun said:
Given the differential equation [math]y'=4x^3y^3[/math] with initial condition [math]y(1)=0[/math]determine what the existence and uniqueness theorem can conclude about the IVP.

I know the Existence and Uniquness theorem has two parts 1)check to see if the function is differentiable and 2)check to see if $$\frac{\partial f}{\partial y}$$ is continious. If they both are true you can condlude there is only one solution (a unique solution). If not, then you can't conclude anything.

My problem is I don't understand which function I should be checking. Should I be checking the differential equation it self, or do I first need to solve and and then check the (a) solution?

The initial value problem is of the form:

$$\left\{\begin{matrix}
y'=f(x,y)\\
\\
y(x_0)=y_0
\end{matrix}\right.$$

Therefore, the function $f$ is equal to $4x^3y^3$.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
536
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
Replies
0
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
1
Views
2K
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K