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asdf12312
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Homework Statement
Homework Equations
The ratio of the parameters [itex]\frac{E_1}{E_2}[/itex] to find the gain (in dB), 10[itex]\times[/itex]log10[itex]\frac{E_1}{E_2}[/itex].
"To determine the gain factor in part 8, first think about what happens to the energy when you multiply the signal by a constant factor. Then use the logarithmic formula above to solve for the gain factor."
The Attempt at a Solution
Since energy is square of integral of a f(x), I am thinking if f(x) is multiplied by constant factor then energy will be square of that factor greater. I already have E1 of the problem, which is the energy of f(x) above = 2.99. I am confused I think because problem says 5dB then 4dB. anyway..if I assume gain of energy is equal to 4dB i have:
4dB = 10[itex]\times[/itex]log10[itex]\frac{E_1}{E_2}[/itex]
0.4 = log10[itex]\frac{E_1}{E_2}[/itex]
[itex]\frac{E_1}{E_2}[/itex] = 2.512 → E2 = [itex]\frac{2.99}{2.512}[/itex] = 1.19
but why is the energy less than the original though? am i doing this right so far??