- #1
bonbon22
- 92
- 5
- Homework Statement
- The spring constant of a helical spring is 28 N mñ1. A 0.40 kg mass is suspended from the
spring and set into simple harmonic motion of amplitude 60 mm.
- Relevant Equations
- 1/2 F * change in extension = E
1/2 k * x^2 = E
The spring constant of a helical spring is 28 N mñ1. A 0.40 kg mass is suspended from the
spring and set into simple harmonic motion of amplitude 60 mm.
i use the equation 1/2 change in extension times by force where the force i assume is mass times by 9.8
but the mark scheme uses 1/2 kx ^2 and arrives at a different answer I am missing something but i don't know what it is?
the answer i got 0.392
answer in mark scheme 0.56
spring and set into simple harmonic motion of amplitude 60 mm.
i use the equation 1/2 change in extension times by force where the force i assume is mass times by 9.8
but the mark scheme uses 1/2 kx ^2 and arrives at a different answer I am missing something but i don't know what it is?
the answer i got 0.392
answer in mark scheme 0.56