- #1
silencecloak
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Homework Statement
Upon spotting an insect on a twig overhanging water, an archer fish squirts water drops at the insect to knock it into the water. Although the fish sees the insect along a straight-line path at angle φ and distance d, a drop must be launched at a different angle θ0 if its parabolic path is to intersect the insect. If φ = 38.0° and d = 0.900 m what θ0 is required for the drop to be at the top of the parabolic path when it reaches the insect?
Homework Equations
Vy=V0sin[tex]\theta[/tex]
max height =V02sin[tex]\theta[/tex]2 / 2g
V2 = V02+2a(x-x0)
The Attempt at a Solution
Solving for the triangle gave me a height of .55m and a length of .709 m
Using these values to solve for V02 I ended up with V02 = 3.727.
Plugging these values into the max height formula and solving sin2[tex]\theta[/tex] = 2*g*h / 3.7272 gave me a theta value of 61.75 degrees
did i solve this correctly?
Thanks!