- #1
Varon
- 548
- 1
Even if you send a buckyball molecule in the emitter, does the detector always give you output in terms of electrons? Isn't there a way to actually check the buckyball located in the detector?
Because in normal double slit with electrons. One can argue that the emitter send an electron field that is splitted by the slits into waves, and the waves reach the detector that trigger just one of the existing electrons at the detectors due to conservation of energy. Why not?
Can you suggest ways to eliminate this possibilility by making use of other methods to detect the electron emitted (to distinguish it from the thousands of existing electrons at the detector)?
Because in normal double slit with electrons. One can argue that the emitter send an electron field that is splitted by the slits into waves, and the waves reach the detector that trigger just one of the existing electrons at the detectors due to conservation of energy. Why not?
Can you suggest ways to eliminate this possibilility by making use of other methods to detect the electron emitted (to distinguish it from the thousands of existing electrons at the detector)?