- #1
pardesi
- 339
- 0
surely [tex]\vec{\nabla} \times \vec{B} \neq 0[/tex] in general
but the work done by magnetic field on any charge is 0 hence is independent of the path taken
So can we call such a field conservative
but the work done by magnetic field on any charge is 0 hence is independent of the path taken
So can we call such a field conservative