Are my answers correct? Quadratic and logarithmic modeling

In summary: Thanks again for your help!In summary, for the given conversation, there are two options for replacement packs with different models. Option 1 has a quadratic model with a monthly access fee of $20 and an included 20 gigabytes, with a cost of $0.50 for each additional gigabyte. Option 2 has a logarithmic model with a monthly access fee of $30 and an included 25 gigabytes, with a cost of $0.50 for each additional gigabyte. To develop these equations, the quadratic model is solved by elimination and the logarithmic model is solved by finding the value of the variables a and b.
  • #36
needalgebra said:
the graph was going to be my next question! - sorry for being a pain in the butt. :p

How would would i put my answers into WA?

Use the command:

y=x^2/2+20,y=30+ln(x+1)/(2ln(2)) where x=0 to 8
 
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  • #37
why is logarithmic model pretty much staying the same...

they're both supposed to go up by 50 cents, same amount.

im confused
 
  • #38
The both go up by 50 cents for the first gigabyte, but only a linear function will change at a constant rate.
 

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