- #1
Damidami
- 94
- 0
I think I'm not understanding something here:
A point [itex]L \in \mathbb{R}[/itex] is a limit point of a sequence [itex] a_n[/itex] if exists a subsequence [itex]b_n[/itex] such that [itex]\lim b_n = L[/itex]
So for example the constant sequence [itex]a_n = 1[/itex] so that [itex]a = 1, 1, 1, 1, 1, 1, \ldots [/itex] has a unique limit point [itex]L=1[/itex]
But a limit point (or acumulation point) is one that can be approached by nearby point in the set. (For example in the open interval [itex](0,2)[/itex] we have that 2 is al limit point, but in the set [itex]S=\{ 1 \}[/itex] we have no limit point (1 is an isolated point in [itex] \mathbb{R}[/itex])
Aren't both definitions of limit point contradictory? What am I doing wrong?
Thanks
A point [itex]L \in \mathbb{R}[/itex] is a limit point of a sequence [itex] a_n[/itex] if exists a subsequence [itex]b_n[/itex] such that [itex]\lim b_n = L[/itex]
So for example the constant sequence [itex]a_n = 1[/itex] so that [itex]a = 1, 1, 1, 1, 1, 1, \ldots [/itex] has a unique limit point [itex]L=1[/itex]
But a limit point (or acumulation point) is one that can be approached by nearby point in the set. (For example in the open interval [itex](0,2)[/itex] we have that 2 is al limit point, but in the set [itex]S=\{ 1 \}[/itex] we have no limit point (1 is an isolated point in [itex] \mathbb{R}[/itex])
Aren't both definitions of limit point contradictory? What am I doing wrong?
Thanks