Are the S' Axes Nonorthogonal in a Spacetime Diagram?

Click For Summary
The discussion focuses on demonstrating that the S' axes, x' and ct', are nonorthogonal in a spacetime diagram, starting from the condition that t = t' = 0 when x = x' = 0. Participants emphasize the importance of using the Lorentz transformations and suggest that a diagram is essential for visualizing the problem. One user initially struggles with the concept but later confirms they have solved it after class instruction, which involved trigonometry. There is also a request for the solution from another participant, indicating a need for clarity on the topic. The conversation highlights the connection between theoretical understanding and practical application in spacetime diagrams.
Broseidon
Messages
4
Reaction score
0

Homework Statement


Show that the S' axes, x' and ct', are nonorthogonal in a spacetime diagram. Assume that t = t' = 0 when x = x' = 0. (Hint: use the fact that the ct' axis is the world line of the origin of S' to show that the ct' axis is inclined with respect to the ct' axis. Next, note that the world line of a light pulse moving in the +x direction starting out at x = 0 and ct = 0 is described by the equation x = +ct in S and x' = ct' in S').


Homework Equations


-The Lorentz transformations
-Relativistic velocity transformation


The Attempt at a Solution


I know it isn't much (and maybe foolish), but I felt like I didn't have much to go on about, so I tried trigonometry and somehow obtain an expression for sin not equal to one (or cosine not equal to zero).


All help is appreciated, and thank you in advance! (:
 
Physics news on Phys.org
Hello Bro and welcome to PF. Suppose I don't know what S and S' stand for ?
Also: check the phrase "ct' axis is inclined with respect to the ct' axis".

You may suppose someone wanting to help you is familiar with the Lorentz transformations. My first impression is that you don't need velocity transformation formulas.

The problem asks you to show something in a diagram. So your attempt at a solution should be a diagram or a (fairly detailed, you know: 1 pic = 1k words...) description of a diagram.

There is no reason to feel like you don't have much to go on: this is asking for something you are supposed to have learned in the material preceding the exercise...

I'm turning in, but there are others to help you as well. Help them a little, please!
 
Dear BvU,
I am fortunate enough to have solved it. I thank you for being willing to help. (: The professor solved it in class and it indeed involves some trigonometry.
 
do you have the solution. i need it pleaase:)
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

Replies
6
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 28 ·
Replies
28
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 61 ·
3
Replies
61
Views
6K