- #36
Ilja
- 676
- 83
If one removes one point from the closed universe, it becomes [itex]\mathbb{R}^3\times \mathbb{R}[/itex], so this is not really a problem. Harmonic coordinates would exist there (I have seen them but forgotten where).PAllen said:Note, this rules out a closed universe, thus you can't handle a universe with high energy density.
The more serious point is that such solutions would not define anymore a homogeneous universe. Thus, the interpretation favors a flat universe as the only homogeneous one.
But there is no inability to handle universes with high energy density. There may be no such homogeneous solutions, but so what, it means they become inhomogeneous.