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DarPodo
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Homework Statement
A helicopter is flying in a straight line over a level field at a constant speed of 6.8 m/s and at a constant altitude of 9.9 m. A package is ejected horizontally from the helicopter with an initial velocity of 11.0 m/s relative to the helicopter, and in a direction opposite the helicopter's motion.
1)Find the initial velocity of the package relative to the ground.
2)What is the horizontal distance between the helicopter and the package at the instant the package strikes the ground?
3)What angle does the velocity vector of the package make with the ground at the instant before impact, as seen from the ground?
Homework Equations
Vy2=Voy2-2*g*(y-yo)
Vy = Voy+g*t
The Attempt at a Solution
1) To find the initial velocity of the package to the ground I thought it was just a simple vector subtraction of 11m/s - 6.8m/s ... my online homework CAPA says that the result is not correct, but I don't know another method.
2) This problem requires me having the correct solution for part 1. I would use the time taken for the package to hit the ground (using t = v/g) and then do:
(t * the velocity from part 1) + (t*6.8) = distance traveled by the package when it hits the ground. I can't test that out unless I have part 1 correct.
3) Again, I would need part 1 correct, but I'm thinking it's just inverse tan to solve.
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