Area B/w Curves: y=(secx)^2/4 & 4(cosx)^2

  • MHB
  • Thread starter brickair
  • Start date
  • Tags
    Curves
In summary: We do not simply provide answers here, as that is not helpful for the person asking the question.Thank you!
  • #1
brickair
1
0
Determine the area between:

1.) y=((secx)^2)/4 and y=4(cosx)^2

2.) y=e^x , y=e^-4x , and x=ln4

3.) y=5cosx and y=5cos(2x) for 0≤x≤pi
 
Physics news on Phys.org
  • #2
brickair said:
Determine the area between:

1.) y=((secx)^2)/4 and y=4(cosx)^2

2.) y=e^x , y=e^-4x , and x=ln4

3.) y=5cosx and y=5cos(2x) for 0≤x≤pi

The area between $y=f(x)$ and $y=g(x)$ on the interval $[a,b]$, when $f(x) \geq g(x)$ is euqal to $\displaystyle{\int_a^bf(x)-g(x) dx}$.

Can you apply this in your case?
 
  • #3
brickair said:
Determine the area between:

1.) y=((secx)^2)/4 and y=4(cosx)^2

2.) y=e^x , y=e^-4x , and x=ln4

3.) y=5cosx and y=5cos(2x) for 0≤x≤pi

Hello and welcome to MHB!

Just for future reference, we ask that you:

a) Post no more than two questions per thread in your initial post. Follow-up questions are fine, but if you have a new question, please begin a new thread.

b) Show what you have tried, as this gives our helpers a better idea where you are stuck and how best to help. Our goal here is to maximize the learning for the person asking the question by getting them involved in the solution process.
 

FAQ: Area B/w Curves: y=(secx)^2/4 & 4(cosx)^2

What is the area between the curves y=(secx)^2/4 and 4(cosx)^2?

The area between two curves is the region bounded by the two curves. In this case, it is the region between the curves y=(secx)^2/4 and 4(cosx)^2, as shown in the graph below.

How do you find the area between two curves?

To find the area between two curves, you need to first identify the points of intersection between the two curves. Then, you can use the definite integral to find the area between these points. In this case, the definite integral would be ∫(4(cosx)^2 - (secx)^2/4) dx.

What is the relationship between the two given curves?

The two given curves, y=(secx)^2/4 and 4(cosx)^2, are inverse functions of each other. This means that the graph of one curve is a reflection of the other curve about the line y=x. The area between these curves represents the area between the inverse functions.

Are there any special considerations when finding the area between inverse curves?

Yes, when finding the area between inverse curves, you need to pay attention to the limits of integration. Since the curves are reflections of each other, the limits of integration will be different for each curve. This means that you will need to split the definite integral into two parts and apply different limits of integration for each part.

Can the area between two curves be negative?

No, the area between two curves cannot be negative. The definite integral only calculates the area above the x-axis, so it will always result in a positive value. If the area between the curves appears to be negative, it means that the curves intersected in a way that the lower curve was above the upper curve within the given limits of integration.

Similar threads

Replies
20
Views
3K
Replies
2
Views
2K
Replies
1
Views
2K
Replies
1
Views
971
Replies
5
Views
1K
Back
Top