- #1
karush
Gold Member
MHB
- 3,269
- 5
Find the area of the region in the first quadrant
bounded by the line $y=x$, the line $x=2$, the curve $y=\frac{1}{x^2}$
$$\int_{1}^{2}\left(x-\frac{1}{{x}^{2}}\right) \,dx$$
just seeing if this is the way to go.
View attachment 4495
bounded by the line $y=x$, the line $x=2$, the curve $y=\frac{1}{x^2}$
$$\int_{1}^{2}\left(x-\frac{1}{{x}^{2}}\right) \,dx$$
just seeing if this is the way to go.
View attachment 4495