Maybe it's a typo and should read "above $y=b$". That is, find the area inside the circle $x^2+y^2=a^2$ that is located above the line $y=b$, where $-a\le b\le a$.wonguyen1995 said:Find area inside circle x^2+y^2=a^2, above 7=b, -a \le b \le a
Sorry, I don't understand your remark.wonguyen1995 said:?? i think f of y right?
(-a to a) minus (-a to b)?
Evgeny.Makarov said:Maybe it's a typo and should read "above $y=b$". That is, find the area inside the circle $x^2+y^2=a^2$ that is located above the line $y=b$, where $-a\le b\le a$.
Sorry, I don't understand your remark.
The formula for finding the area inside a circle is A = πr^2, where A is the area and r is the radius.
The variable 'b' in this equation represents the y-coordinate of the point where the circle intersects the x-axis. The area inside the circle above b=7 would be the portion of the circle that lies above the line y=7. This would result in a smaller area compared to the full circle with radius a.
No, the area inside a circle cannot be negative. It is always a positive value, as it represents the amount of space enclosed by the circle.
The value of 'a' represents the radius of the circle. As 'a' increases, the area of the circle also increases. However, in the case of x^2+y^2=a^2 above b=7, the value of 'a' does not have a direct effect on the area above b=7, as it only affects the size of the entire circle.
No, the area inside a circle above b=7 will vary depending on the value of 'a'. As 'a' increases, the area of the circle increases, but the area above b=7 remains the same. However, if 'a' is kept constant, the area above b=7 will also be constant as long as the circle intersects the x-axis at y=7.