Arithmetic mean and geometric mean

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The discussion focuses on finding the minimum value of the expression [1/(1+ab)] + [1/(1+bc)] + [1/(1+ac)] given that a² + b² + c² = 3 for positive real numbers a, b, and c. It is noted that the inequality A² + B² + C² ≥ AB + AC + BC can be applied to derive insights into the problem. The minimum value of the expression is determined to be 3/2. Participants are reminded that only hints and guidance can be provided for homework-type questions, emphasizing the importance of showing work in problem-solving. The discussion underscores the relevance of inequalities in optimizing expressions involving positive real numbers.
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Homework Statement
Arithmetic mean and geometric mean
Relevant Equations
Arithmetic mean and geometric mean
If a, b, and c are positive real numbers and a² + b² + c² = 3, what is the minimum value of the expression [1/(1+ab)] + [1/(1+bc)] + [1+(1+ac )]?

Usage: A² + B² + C² ≥ AB+AC+BC

Answer: 3/2
 
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On any homework-type of question we are only allowed to give hints and guidance regarding the work that you show. You must show work on this problem.

PS. Your "Usage" statement for general A, B, C could be stronger.
 
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Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
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