- #1
KICKERMAN360
- 2
- 0
Homework Statement
A 110 g arrow is shot vertically from a bow whose effective spring constant is 500 N/m
If the bow is drawn 55 cm before shooting the arrow, to what height does the arrow rise?
Homework Equations
F=ma
U=kx^2 - for Spring (bow)
F=-kx
KE=1/2 mv^2
W=fs
The Attempt at a Solution
I found by using:
F=500 * .55
= 275N
The arrow moves upwards at 275N
It therefore accelerates at:
F=ma
a= F/m
= 275/.110
Gravity is assumed to be -9.8.
Thanks for any help
Last edited: