How Does Acceleration Affect an Astronaut's Apparent Weight Near the Moon?

In summary, the apparent weight of a 75-kg astronaut 4200 km from the center of the Earth's Moon in a space vehicle is 21 Newtons towards the moon when the vehicle is moving at constant velocity. When the vehicle is accelerating towards the moon at 2.9 m/s^2, the apparent weight will be less than 21 Newtons towards the moon, as the astronaut is experiencing a downward acceleration. This can be calculated using the equation Fg = G * [(m1 * m2) / d^2], with the given values of mass of the moon, mass of the astronaut, distance, and gravitational constant G. In the second case, the direction of the apparent weight will be towards the
  • #1
N_L_
33
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What is the apparent weight of a 75-kg astronaut 4200 km from the center of the Earth's Moon in a space vehicle (a) moving at constant velocity, and (b) accelerating toward the Moon at 2.9 m/s^2? State the "direction" in each case.

I understand part a. I got 21 Newtons towards the moon by using Fg = G * [ (m1 * m2) / d^2 ].

For part B I do not understand where / how to use the acceleration of 2.9 m/s^2...would it be the same equation?

mass of the moon: 7.35 x 10^22 kg
mass of the astronaut: 75 kg
distance: 4200 km = 4200000 meters
G = 6.67 x 10^-11
 
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  • #2
N_L_ said:
What is the apparent weight of a 75-kg astronaut 4200 km from the center of the Earth's Moon in a space vehicle (a) moving at constant velocity, and (b) accelerating toward the Moon at 2.9 m/s^2? State the "direction" in each case.

I understand part a. I got 21 Newtons towards the moon by using Fg = G * [ (m1 * m2) / d^2 ].

For part B I do not understand where / how to use the acceleration of 2.9 m/s^2...would it be the same equation?

mass of the moon: 7.35 x 10^22 kg
mass of the astronaut: 75 kg
distance: 4200 km = 4200000 meters
G = 6.67 x 10^-11

Remember that "apparent weight" is a fancy term for "normal force." In the first case the normal force and the weight are going to be the same magnitude because the astronaut is not accelerating. The accelerating case is very similar to an elevator problem, where the elevator is accelerating downward at a rate less than g.

-Dan
 
  • #3
N*m^2/kg^2

In order to calculate the apparent weight of the astronaut in a space vehicle that is accelerating towards the Moon at 2.9 m/s^2, we need to take into account the gravitational force and the acceleration force acting on the astronaut. The gravitational force is given by the equation Fg = G * [ (m1 * m2) / d^2 ], where G is the gravitational constant, m1 is the mass of the Moon, m2 is the mass of the astronaut, and d is the distance between the center of the Moon and the astronaut.

In this case, the gravitational force will be directed towards the center of the Moon, since the astronaut is 4200 km from the center of the Moon. This force will remain constant throughout the astronaut's journey towards the Moon.

However, the acceleration force will change as the space vehicle accelerates towards the Moon. The acceleration force is given by the equation F = m * a, where m is the mass of the astronaut and a is the acceleration towards the Moon. This force will also be directed towards the center of the Moon, since the acceleration is in that direction.

To calculate the apparent weight of the astronaut, we need to add these two forces together. The result will be the net force acting on the astronaut, which can be used to calculate the apparent weight using the equation F = m * g, where g is the gravitational acceleration on the Moon's surface.

Therefore, the apparent weight of the astronaut in the space vehicle accelerating towards the Moon will be the sum of the gravitational force and the acceleration force, directed towards the center of the Moon. This will result in a larger apparent weight compared to the astronaut's weight on Earth or in a space vehicle moving at constant velocity, since the acceleration force adds to the gravitational force.
 

FAQ: How Does Acceleration Affect an Astronaut's Apparent Weight Near the Moon?

What is the "Astronaut on the moon problem"?

The "Astronaut on the moon problem" is a hypothetical scenario used in physics to demonstrate the concept of conservation of momentum. It involves an astronaut standing on the surface of the moon and throwing a ball backwards.

What is conservation of momentum?

Conservation of momentum is a fundamental principle in physics that states that the total momentum of a closed system remains constant. This means that the total momentum before an event must be equal to the total momentum after the event.

What happens to the astronaut and the ball in the "Astronaut on the moon problem"?

In the "Astronaut on the moon problem", the astronaut and the ball experience a change in momentum. When the astronaut throws the ball backwards, the ball gains momentum in the opposite direction, causing the astronaut to move in the opposite direction as well. This is due to the conservation of momentum.

How does the mass of the astronaut and the ball affect the outcome of the "Astronaut on the moon problem"?

The mass of the astronaut and the ball do not affect the outcome of the "Astronaut on the moon problem". According to the principle of conservation of momentum, the change in momentum of the ball and the astronaut will be equal and opposite regardless of their masses.

Why is the "Astronaut on the moon problem" important in physics?

The "Astronaut on the moon problem" is important in physics because it illustrates the principle of conservation of momentum, which is essential in understanding the behavior of objects in motion. It also helps to explain the concept of action and reaction forces, which are fundamental in many physical phenomena.

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