- #1
slow
- 93
- 16
Hi. I put the simplest case. A capacitor formed by two flat metal plates faced in the vacuum, with charges of the same absolute value in both plates. In this case, the electric field of the capacitor, in a static situation, has an energy expressed in the following way.
[tex]E=\dfrac{q^2}{2 \ C}[/tex]
Now my doubt. One of the plates is touched by something that changes the value of the charge on that plate. The charge of the other plate has not changed. Now the capacitor is charged asymmetrically. How is the energy of the electric field expressed in this case?
[tex]E=\dfrac{q^2}{2 \ C}[/tex]
Now my doubt. One of the plates is touched by something that changes the value of the charge on that plate. The charge of the other plate has not changed. Now the capacitor is charged asymmetrically. How is the energy of the electric field expressed in this case?