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Conquest Ace
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Yeah I cannot figure this out...
.A cannon fires a cannonball 500.0m downrange when set at a 45.0o angle. At what velocity does the cannonball leaves the cannon?
Given Angle : 45
Distance: 500m
Vi : ?
dy = viy(t)+ 4.9(t)^2
Only thing I figured out is that vix = viy
and that t = 500/vicos45
Homework Statement
.A cannon fires a cannonball 500.0m downrange when set at a 45.0o angle. At what velocity does the cannonball leaves the cannon?
Given Angle : 45
Distance: 500m
Vi : ?
Homework Equations
dy = viy(t)+ 4.9(t)^2
The Attempt at a Solution
Only thing I figured out is that vix = viy
and that t = 500/vicos45
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