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waterwalker10
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Homework Statement
The M61 Vulcan cannon is a Gatling Gun-type weapon deployed on an aircraft. It fires a 100g, 20mm diameter projectile at a rate of up to 6,000 shots per minute. Barrel length is 170cm, and muzzle velocity (speed of the projectile leaving the barrel) is 1030 m/s.
-Assuming constant acceleration, what is the mean (average) velocity of the projectile in the barrel?
(It has been 8 years since a physics class...not looking for an answer but an arrow in the correct direction. Thank you)
Homework Equations
V=D/T
[tex]\overline{V}[/tex] = [tex]\Delta[/tex] Distance/Time
[tex]V^{2}[/tex]=[tex]V^{2}_{0}[/tex] + 2as
The Attempt at a Solution
Where do I start...I began with the second equation. V = 170cm / T Well if it shoots 6000rpm then it would be broken down to 100rps. Given that I would say that fires a bullet every .01 seconds. Plug the variables into the equation.
V = 170 cm / .01 sec or 17000cm or 170m/s
If you see the muzzle velocity of 1030m/s then you would know right off the bat that 170m/s is wrong.
So I used the second equation...and came up with some crazy answer that I know is definitely wrong. See below...
10302 = [tex]1030^{2}_{0}[/tex] + 2a170
1060900 = 0 (Initial Bullet Velocity is zero) + 2a170 (Solve for A)
a = V2/2*170cm
a = 1060900/340cm or 3120.29cm or 312,029 meters
Plug back into the equation
1060900 = 0 + 2*312,029*1.7
And they magically equal. Some how I think I might be using the wrong equation but I need someone to help me.