Average force between an object and non-movable object?

In summary, a golf ball with a mass of 41.8 g is dropped from a height of 1.41 m onto a hard floor and bounces back to the same height. The problem asks for the average force on the ball during the 0.012 s it is in contact with the floor. To calculate this, the change in velocity must be determined, but since the ball returns to the same height, the initial and final velocities are both zero. However, the velocities at ground level must be calculated, which can be done by using the equation v = at, where a is the acceleration due to gravity (9.8 m/s^2) and t is the time (0.012 s).
  • #1
sirfinklstin
15
0

Homework Statement



A golf ball of mass 41.8 g is dropped from a height h = 1.41 m onto a hard floor and bounces back to exactly that same height. What is the average force (in N) on the ball during the 0.012 s that it was in contact with the floor?

Homework Equations



Impulse = Ft
Impulse = m(Vf - Vi)

The Attempt at a Solution


I am not quite sure how to proceed with this problem, becuase I am completely clueless as to how I should go about calculating the change in velocity, becuase if the ball returns to the same height, (no friction of air resistance) then arent the Vi and Vf both = 0?
 
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  • #2
Hi sirfinklstin! :smile:
sirfinklstin said:
A golf ball of mass 41.8 g is dropped from a height h = 1.41 m onto a hard floor and bounces back to exactly that same height. What is the average force (in N) on the ball during the 0.012 s that it was in contact with the floor?

how I should go about calculating the change in velocity, becuase if the ball returns to the same height, (no friction of air resistance) then arent the Vi and Vf both = 0?

Yes, but you want the two velocities at ground level. :wink:
 
  • #3
How would the velocities be calculated? 0 + (9.8 m/s)(1.41m)?
 
  • #4
sirfinklstin said:
How would the velocities be calculated? 0 + (9.8 m/s)(1.41m)?

what? v = as ?? :confused:
 

FAQ: Average force between an object and non-movable object?

What is the definition of "average force"?

The average force between an object and a non-movable object is the measure of the overall force exerted on the object over a specific period of time. It takes into account both the magnitude and direction of the force.

How is the average force calculated?

The average force can be calculated by dividing the total force exerted on the object by the time period over which the force was applied. This can be represented by the formula: Average Force = Total Force / Time.

What factors can affect the average force between an object and a non-movable object?

The average force can be affected by factors such as the mass and velocity of the object, the type of surface the object is in contact with, and the duration of time for which the force is applied.

Is the average force always constant?

No, the average force between an object and a non-movable object may not always be constant. It can vary depending on the factors mentioned above and can also change over time as the conditions of the interaction between the two objects change.

Why is it important to calculate the average force between an object and a non-movable object?

Calculating the average force can help us understand the effects of the interaction between an object and a non-movable object. It can also help us make predictions and optimize designs for different scenarios, such as minimizing the force exerted on an object to reduce wear and tear on it.

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