- #1
brycenrg
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Homework Statement
Baseball(0.145kg) pitch is pitched horizontally at 32m/s, ball pops straight up to a height of 36.5m. If the contact time between bat and ball is 2.5ms, calculate the average force between the ball and the batt during contact.
Homework Equations
Favg = Δp/t
KE=KE
The Attempt at a Solution
1/2mv^2 = mgh
v= squar(2gh)
Find Vo when ball leaves bat
((0.145kg*27m/s)-(0.145kg*32m/s))/Tcontact = -290 N
My answer is wrong, in my solution manual it breaks the variables up into x and y. Then it uses Pythagoras equation for the hypotenus. Is that okay to do for forces? i thought that was only used for velocity vectors or.. Ima little confused.
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