Avg Power in a Rotational Energy/Work Problem

In summary, the average power in a rotational energy or work problem is calculated by determining the work done on an object as it rotates and the time it takes for that work to be done. The formula for average power is the total work done divided by the time interval during which the work occurs. In rotational systems, work can be expressed in terms of torque and angular displacement, allowing for the analysis of rotational motion in terms of power. Understanding these concepts is crucial for solving problems involving rotating bodies in physics.
  • #1
dcmf
16
5
Homework Statement
Consider a motor that exerts a constant torque of 25.0 N⋅m to a horizontal platform whose moment of inertia is 50.0 kg⋅m^2. Assume that the platform is initially at rest and the torque is applied for 12.0 rotations. Neglect friction.

What is the average power Pavg delivered by the motor in the situation above? Enter your answer in watts to three significant figures.
Relevant Equations
K = (1/2)Iw^2
W = τΔθ
P = W/Δt
This question has multiple parts and according to all the work done up to this point...

How much work W does the motor do on the platform during this process?​
1885 J​
What is the rotational kinetic energy of the platform Krot,f at the end of the process described above?​
1885 J​
What is the angular velocity ωf of the platform at the end of this process?​
8.68 rad/s​
How long Δt does it take for the motor to do the work done on the platform calculated in Part A?​
17.4 s​

Now I'm being asked...

What is the average power Pavg delivered by the motor in the situation above?​
???​

I assumed to find average power I would need average work, especially because the question's hint prompted me to find the average angular velocity, which it confirmed to be 4.34 rad/s. So I did the following calculations:
1711247294014.png

27.1 W was not accepted as the answer. Any advice on adjustments to make to my equation? Is there a rounding error?
 
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  • #2
dcmf said:
I would need average work
How would you define that?
What is the definition of average power? You wrote ##P_{avg}=W/\Delta t##, which is correct if you define that W appropriately.
 
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  • #3
haruspex said:
How would you define that?
What is the definition of average power?

In class, we actually did not address work or power in the context of problems involving rotation. This homework question seems to to be presented like a way to self-learn the material, but we were not provided with an equation to work with, so I assumed I should use the P=W/Δt equation.

I'm not sure how P differs from Pavg. According to one website I just found, "average power as the total energy consumed divided by the total time taken". Would this be accurate?

If so, would doing the calculation as...
Pavg = W tot/Δttot = 1884.95559 J / 17.36646 s = 108.54 W​
(using unrounded versions of earlier values) and then rounding to 3 sig figs (109 W) be the right way to set up and solve the equation according to the above definition?
 

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  • #4
haruspex said:
How would you define that?
What is the definition of average power? You wrote ##P_{avg}=W/\Delta t##, which is correct if you define that W appropriately.
I just noticed that you may have updated your reply. Would it be appropriate to use the work as defined in the first part of the question that asks "How much work W does the motor do on the platform during this process?"
 
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  • #5
I would set the work aside. You are asked to find the average power over time. The time average of a function ##f(t)## over an interval ##T## is $$f_{\text{avg.}}=\frac{\int_0^T f(t)~dt}{\int_0^T dt}.$$ Think of the equivalent linear situation when you have a constant force acting on an object and the velocity is not constant. In that case, the power delivered to the object is given by $$P(t)=Fv(t)$$where ##v## is the instantaneous linear velocity. In this case you have a constant torque. What do you think the equivalent equation would be for rotations?

Put it together and you will discover why the problem asked you to find the average angular velocity first.
 
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  • #6
kuruman said:
I would set the work aside.
Why?
kuruman said:
The time average of a function ##f(t)## over an interval ##T## is $$f_{\text{avg.}}=\frac{\int_0^T f(t)~dt}{\int_0^T dt}.$$
And in the present case, the numerator is the work done, no?
 
  • #7
haruspex said:
Why?
Please see PM on this.
haruspex said:
And in the present case, the numerator is the work done, no?
Yes.
 

FAQ: Avg Power in a Rotational Energy/Work Problem

What is the formula for average power in a rotational energy/work problem?

The formula for average power in a rotational energy/work problem is given by \( P_{avg} = \frac{\Delta W}{\Delta t} \), where \( \Delta W \) is the work done over the time interval \( \Delta t \). For rotational systems, this can also be expressed as \( P_{avg} = \tau \cdot \omega_{avg} \), where \( \tau \) is the torque and \( \omega_{avg} \) is the average angular velocity.

How do you calculate work done in a rotational system?

Work done in a rotational system is calculated using the formula \( W = \tau \cdot \theta \), where \( \tau \) is the torque applied and \( \theta \) is the angular displacement in radians. This is analogous to the linear work formula \( W = F \cdot d \), where \( F \) is force and \( d \) is displacement.

What is the relationship between torque, angular velocity, and power in rotational motion?

The relationship between torque (\( \tau \)), angular velocity (\( \omega \)), and power (\( P \)) in rotational motion is given by the formula \( P = \tau \cdot \omega \). This indicates that power is the product of the torque applied to a rotating object and its angular velocity.

How can you find the average angular velocity?

The average angular velocity (\( \omega_{avg} \)) can be found using the formula \( \omega_{avg} = \frac{\Delta \theta}{\Delta t} \), where \( \Delta \theta \) is the change in angular displacement and \( \Delta t \) is the time interval over which the change occurs. This is similar to finding average velocity in linear motion.

What units are used for average power in rotational systems?

The units for average power in rotational systems are the same as for linear systems: Watts (W). One Watt is equivalent to one Joule per second (J/s). In rotational systems, torque is measured in Newton-meters (Nm) and angular velocity is measured in radians per second (rad/s), so power calculated as \( P = \tau \cdot \omega \) will also be in Watts.

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