- #1
NotMrX
- 97
- 0
If a car gradually changes a direction of 90 degrees at constant speed of 200 m/s over a time period of 20 seconds, then what is the accelleration?
I don't know if the way I worked it was correct. I think the only assumption is that the acceleration is constant.
[tex]a_x=\frac{v_xf-v_xi}{t}=\frac{0-200}{20}=-10[/tex]
[tex]a_y=\frac{v_yf-v_yi}{t}=\frac{200-0}{20}=10[/tex]
[tex]a=\sqrt{a_x^2+a_y^2}=\sqrt{(-10)^2+10^2}=10\sqrt{2}[/tex]
Does this seem right to you?
I don't know if the way I worked it was correct. I think the only assumption is that the acceleration is constant.
[tex]a_x=\frac{v_xf-v_xi}{t}=\frac{0-200}{20}=-10[/tex]
[tex]a_y=\frac{v_yf-v_yi}{t}=\frac{200-0}{20}=10[/tex]
[tex]a=\sqrt{a_x^2+a_y^2}=\sqrt{(-10)^2+10^2}=10\sqrt{2}[/tex]
Does this seem right to you?